Removed test code sudoku
- Author
- Maarten 'Vngngdn' Vangeneugden
- Date
- Jan. 2, 2018, 11:46 a.m.
- Hash
- 0c4f23302352cc926717cb940bce0d39a3ea756e
- Parent
- 9eb09c5285e15eb2d77a892bb79f3162a1c7b0d4
- Modified file
- sudoku-solver.py
sudoku-solver.py ¶
2 additions and 0 deletions.
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sudoku-solver.py - A simple program that can solve any (solvable) sudoku puzzle. |
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Copyright 2016 Maarten 'Vngngdn' Vangeneugden |
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|
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Licensed under the Apache License, Version 2.0 (the "License"); |
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you may not use this file except in compliance with the License. |
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You may obtain a copy of the License at |
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|
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https://www.apache.org/licenses/LICENSE-2.0 |
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|
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Unless required by applicable law or agreed to in writing, software |
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distributed under the License is distributed on an "AS IS" BASIS, |
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WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. |
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See the License for the specific language governing permissions and |
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limitations under the License. |
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""" |
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|
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""" |
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This sudoku solver takes a recursive approach to solve a given sudoku. |
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Although there are many different variations and types of sudokus, this program |
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only handles NxN sudokus (i.e. squares with root-subgrids, like the most common |
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9x9). So if you want hexadecimal plays, you can totally do that. |
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""" |
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|
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# Imports: |
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from math import sqrt # For the roots of the sudoku length. |
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|
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# Constants: |
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EMPTY = 0 |
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|
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# Prints the given sudoku to the terminal in a readable way: |
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def print_sudoku(sudoku): |
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# In order to print in a clean way, we first have to determine the length of |
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# the biggest number: |
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biggestNumber = 0 |
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for row in sudoku: |
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for number in row: |
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if number > biggestNumber: |
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biggestNumber = number |
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|
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rootNumber = 10 |
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digits = 1 |
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while rootNumber**digits < biggestNumber: |
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digits += 1 |
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# And now we've got the largest amount of digits. |
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|
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for row in sudoku: |
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for number in row: |
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# XXX: Even though the next line looks a bit dirty, it's a great way |
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# to deduce the required amount of whitespace for readable output. |
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# It takes the highest amount of digits, subtracted with the current |
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# number's digits. so 10 in a sudoku with max. 3 digits: 3-2+1 = 2 |
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# whitespaces. |
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spaces = " " * (digits-len(str(number)) + 1) |
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print(str(number) + spaces, end="") |
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|
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for i in range(0, digits): |
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# And after each row, a seperation whitespace. |
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print() |
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|
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|
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|
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|
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# Given an empty sudoku, the solution is very simple. |
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# Although this is mainly a small optimization, as it is only usable when the |
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# root solution is possible. |
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def solve_empty_sudoku(sudoku): |
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n = sqrt(len(sudoku)) |
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|
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for i in range(0, n*n): |
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for j in range(0, n*n): |
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sudoku[i][j] = (i*n + i/n + j) % (n*n) + 1; |
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return sudoku |
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|
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|
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# Checks if the given sudoku qualifies as a root solution. |
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# This function mainly serves as a silly optimization to check beforehand |
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# whether we have to do the entire backtrack. |
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def is_possible_root_solution(sudoku): |
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root_solution = solve_empty_sudoku() |
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for x in range(0, len(root_solutxon)): |
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for y in range(0, len(root_solution[x])): |
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if sudoku[x][y] != root_solution[x][y] and sudoku[x][y] != EMPTY: |
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return False |
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# when here, all the sudoku can be filled as a root solution. |
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return True |
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|
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# Checks whether the given number already exists in the given array. |
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def exists_in_array(x, y, value, sudoku): |
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if value == EMPTY: |
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return False # Just... of course. |
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|
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for i in range(0, len(sudoku)): |
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if sudoku[i][y] == value: # No need to check for empty |
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return True |
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return False |
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|
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# Checks whether the number on the given location is unique in its column. |
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def exists_in_column(x, y, value, sudoku): |
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if value == EMPTY: |
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return False |
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|
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for i in range(0, len(sudoku[x])): |
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if sudoku[x][i] == value: |
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return True |
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return False |
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|
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# Checks whether the number on the given location is unique in its "root grid". |
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def exists_in_grid(x, y, value, sudoku): |
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if value == EMPTY: |
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return False |
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|
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# We're going to find out now in which part of the grid the (x,y) is put. |
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# The idea I'm going for : |
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# I'll first try to find out in which segment of the sudoku the value is in. |
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# When I've found it, I trim the data to that segment, after I'll be |
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# checking on that segment only. |
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n = int(sqrt(len(sudoku))) # Determining the square root of the sudoku's length. |
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|
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# The following algorithm is able to handle all square sudokus. |
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A = x%n |
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B = y%n |
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for i in range(0, n): |
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for j in range(0, n): |
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C = x - A + i |
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D = y - B + j |
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if sudoku[C][D] == value and (C != x and D != y): |
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return True |
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return False |
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|
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# Checks whether the sudoku still contains empty grids. Returns false if not, |
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# and vice versa. |
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def is_filled_sudoku(sudoku): |
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for x in range(0, len(sudoku)): |
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for y in range(0, len(sudoku[x])): |
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if sudoku[x][y] == EMPTY: |
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return False |
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return True |
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|
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# Looks from the upper left grid to the lower right grid of the sudoku to find |
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# an empty grid. If it encounters an empty grid, the respective (x,y) |
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# coordinates are returned. |
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# If no empty grid is being found, both returned values will be -1. |
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def find_first_empty_grid(sudoku): |
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for x in range(0, len(sudoku)): |
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for y in range(0, len(sudoku[x])): |
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if sudoku[x][y] == EMPTY: |
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return x, y |
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# When we get to this point, there's no empty grid anymore in the sudoku. |
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raise Exception(""" |
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The given sudoku does not feature any empty grids. Assert that you've |
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given the sudoku to the is_filled_sudoku() function. |
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""") |
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|
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# Works identical to the other function, but looks for the first grid with the |
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# smallest amount of possibilities. So grids with 2 possibilities are returned, |
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# even if an empty grid was found already, having 5 possibilities. |
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def find_first_empty_grid_optimized(sudoku, possibilities): |
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i = 0 |
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j = 0 |
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minimum = len(sudoku)+1 # +1 guarantees 1 will always be chosen. |
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for x in range(0, len(sudoku)): |
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for y in range(0, len(sudoku[x])): |
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if sudoku[x][y] == EMPTY: |
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if len(possibilities[x][y]) < minimum: |
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i, j = x, y |
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minimum = len(possibilities[x][y]) |
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return i, j |
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|
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|
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|
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# Checks whether assigning the given value to the given coordinate in the sudoku |
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# still renders the sudoku valid. |
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def is_valid_assignment(x, y, value, sudoku): |
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if exists_in_array(x, y, value, sudoku): |
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return False |
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if exists_in_column(x, y, value, sudoku): |
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return False |
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if exists_in_grid(x, y, value, sudoku): |
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return False |
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return True |
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|
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# Collects all symbols that can be placed in the given place. |
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def collect_possible_entries(sudoku, x, y): |
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# The strategy is simple: Iterate over all possibilities, and check whether |
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# it's possible or not. |
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possible_values = set() |
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for value in range(1, len(sudoku)+1): |
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if is_valid_assignment(x, y, value, sudoku): |
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possible_values.add(value) |
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return possible_values |
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|
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# Updates the possibilities, in function of the given position. |
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def remove_possibility(sudoku, possibilities, x, y): |
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for i in range(len(possibilities)): |
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for j in range(len(possibilities[i])): |
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# i==x XOR j==y |
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if (i==x and j!=y) or (i!=x and j==y): |
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# The next if-test is necessary to avoid a KeyErrro. |
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if sudoku[x][y] in possibilities[i][j]: |
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#assert (i != x and j == y) or ( |
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possibilities[i][j].remove(sudoku[x][y]) |
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# Removal of possibilities in grid: |
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n = int(sqrt(len(sudoku))) # Determining the square root of the sudoku's length. |
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A = x%n |
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B = y%n |
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for i in range(0, n): |
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for j in range(0, n): |
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C = x - A + i |
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D = y - B + j |
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if C!=x and D!=y: |
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if sudoku[x][y] in possibilities[C][D]: |
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assert C != x and D != y |
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possibilities[C][D].remove(sudoku[x][y]) |
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|
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def add_possibility(sudoku, possibilities, x, y, value): |
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for i in range(len(possibilities)): |
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for j in range(len(possibilities[i])): |
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# i==x XOR j==y |
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#if (i==x or j==y) and not (i==x and j==y): |
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if (i==x and j!=y) or (i!=x and j==y): |
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#assert i != x and j != y |
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possibilities[i][j].add(value) |
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# Addition of possibilities in grid: |
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n = int(sqrt(len(sudoku))) # Determining the square root of the sudoku's length. |
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A = x%n |
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B = y%n |
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for i in range(0, n): |
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for j in range(0, n): |
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C = x - A + i |
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D = y - B + j |
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if C!=x and D!=y: |
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assert C != x and D != y |
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possibilities[C][D].add(value) |
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|
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# TODO: For remove/add_possibility: Add √n*√n grid removal as well. |
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|
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|
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# Applies a recursive backtrack algorithm to the given sudoku, in an attempt to |
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# solve it. |
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def recursive_solution(sudoku, possibilities): |
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if is_filled_sudoku(sudoku): |
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return True # The sudoku is solved. |
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else: |
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#x, y = find_first_empty_grid(sudoku) |
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x, y = find_first_empty_grid_optimized(sudoku, possibilities) |
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if len(possibilities[x][y]) == EMPTY: |
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# With an empty grid, there must be a possible value to enter. If there |
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# isn't, that means that somewhere earlier, a possibility was removed, |
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# because the wrong value was added. Thus, this is an impossible |
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# solution, and we must backtrack. |
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return False |
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|
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for i in range(1, 1+len(sudoku)): |
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if i in possibilities[x][y]: |
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# We don't need to test if it's concerning a valid assignment, since |
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# if it weren't a valid assignment, it wouldn't be listed as a |
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# possibility in the first place. |
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sudoku[x][y] = i |
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remove_possibility(sudoku, possibilities, x, y) |
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possibilities[x][y].remove(i) |
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if recursive_solution(sudoku, possibilities) is False: |
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sudoku[x][y] = EMPTY |
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add_possibility(sudoku, possibilities, x, y, i) |
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i = 0 # Reloop over all posibilities (which may have updated |
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# Note how I don't add the tested possibility back, as I did |
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# remove the possibility. That is, because it's clear that |
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# this cannot be a solution if we want to solve the sudoku. |
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# Thus, it shouldn't be added back. |
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else: |
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return True |
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return False |
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|
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# Assertion function. Checks whether the sudoku is a valid, and solved sudoku. |
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def test_solution(sudoku): |
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discovered = [] # This list will be used to store discovered numbers. |
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# Rows: |
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for column in sudoku: |
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for number in column: |
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if number in discovered: |
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return False |
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else: |
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discovered.append(number) |
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discovered.clear() |
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|
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#Columns: |
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for i in range(0, len(sudoku)): |
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for y in range(0, len(sudoku[i])): |
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if y in discovered: |
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return False |
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else: |
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discovered.append(y) |
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discovered.clear() |
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|
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#Grids: |
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# Checking for grids requires us to collect the starting points of said |
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# grids. |
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n = int(sqrt(len(sudoku))) |
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gridPoints = [] |
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for i in range(0, n): |
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gridPoints.append(i*n) |
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|
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for k in gridPoints: |
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for x in range(0,n): |
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for y in range(0,n): |
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if sudoku[x+k][y+k] in discovered: |
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return False |
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else: |
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discovered.append(sudoku[x+k][y+k]) |
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discovered.clear() |
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|
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return True |
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|
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# Prints an introduction paragraph to the user, explaining the details of the |
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# program, and how to operate it properly. |
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def print_introduction(): |
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introduction = """ |
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Welcome to Vngngdn's sudoku solver! |
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I'll explain briefly what you have to do to use this program: |
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After this paragraph, insert the first array of the sudoku, with each |
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grid seperated by 1 space. |
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If there are grids that are empty, use a 0 as placeholder for the empty |
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space. |
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When the row is complete, hit RETURN. |
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The program will then ask for other arrays, until a square sudoku is |
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formed. |
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So, for example, if you enter 9 numbers, and hit RETURN, the program |
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will ask for 8 more arrays, to create a 9x9 sudoku. |
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When the last array has been entered, the program will stop asking for |
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input, and immediately try to solve the sudoku. |
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When the sudoku has been solved, it will print the solution in a |
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readable way. |
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If the sudoku could not be solved, it will print "Failed!", instead of a |
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solution. |
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This indicates the sudoku is most likely invalid, and can't be solved. |
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Off you go now! |
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|
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""" |
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print(introduction) |
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|
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# Asks the user for input. |
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def receive_input(): |
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sudoku = [] # This will be returned in the end. |
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#integers = [] # A list which will be added to the sudoku after input. |
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length = 1 # We know there will be at least 1 number. |
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i = 0 |
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while i < length: |
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integers = [] # A list which will be added to the sudoku after input. |
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integers.clear() |
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# The amount of given numbers implies the remaining amount of rows, |
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# because only square sudokus are handled. |
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line = input() |
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numbers = line.split() # numbers now contains the given numbers. |
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# XXX: Next addition might be redundant after the first one, but it's |
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# still cleaner than having an entire redundant block. |
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length = len(numbers) |
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for number in numbers: |
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integers.append(int(number)) |
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sudoku.append(integers) |
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|
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i += 1 |
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|
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# Current state: The sudoku is completely filled in, including empty spots. |
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# TODO: Add some defensive programming structure, to check for empty spots |
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# in the sudoku. If so, ask the user where to insert the missing numbers. |
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|
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return sudoku |
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|
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|
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|
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# MAIN (sort of) |
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|
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print_introduction() |
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sudoku = receive_input() |
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""" |
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sudoku = [ |
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[0, 0, 0, 0, 9, 0, 4, 2, 0], |
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[0, 0, 0, 0, 0, 0, 0, 0, 8], |
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[9, 0, 0, 1, 0, 0, 3, 0, 0], |
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[0, 3, 0, 0, 5, 8, 9, 1, 0], |
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[0, 0, 0, 9, 0, 3, 0, 0, 0], |
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[0, 1, 9, 4, 2, 0, 0, 5, 0], |
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[0, 0, 5, 0, 0, 6, 0, 0, 4], |
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[6, 0, 0, 0, 0, 0, 0, 0, 0], |
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[0, 2, 7, 0, 8, 0, 0, 0, 0] |
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] |
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""" |
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""" |
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sudoku = [ |
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[2, 0, 0, 0], |
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[0, 0, 1, 0], |
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[0, 3, 0, 0], |
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[0, 0, 0, 4] |
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] |
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""" |
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395 |
|
396 |
396 |
sudoku = [ |
+ |
397 |
sudoku = [ |
397 |
398 |
[0, 0, 0, 0, 1, 5, 8, 0, 6, 0, 0, 0, 7, 0, 0, 2], |
398 |
399 |
[1, 0, 0, 0, 4, 3, 0, 6, 0, 0, 10, 15, 0, 0, 0, 16], |
399 |
400 |
[0, 4, 8, 11, 0, 0, 10, 0, 0, 9, 0, 7, 0, 1, 0, 3], |
400 |
401 |
[9, 0, 5, 16, 2, 0, 0, 15, 0, 0, 8, 13, 10, 0, 0, 0], |
401 |
402 |
[0, 15, 0, 0, 0, 2, 0, 0, 0, 10, 0, 1, 4, 14, 6, 12], |
402 |
403 |
[0, 0, 12, 0, 5, 1, 0, 11, 14, 0, 0, 0, 8, 0, 7, 0], |
403 |
404 |
[0, 0, 0, 10, 0, 0, 6, 14, 0, 12, 0, 0, 0, 3, 0, 11], |
404 |
405 |
[13, 0, 7, 0, 0, 9, 0, 0, 0, 15, 0, 3, 0, 0, 16, 5], |
405 |
406 |
[15, 3, 0, 0, 11, 0, 12, 0, 0, 0, 1, 0, 0, 8, 0, 7], |
406 |
407 |
[5, 0, 10, 0, 0, 0, 1, 0, 7, 4, 0, 0, 15, 0, 0, 0], |
407 |
408 |
[0, 8, 0, 12, 0, 0, 0, 7, 16, 0, 11, 10, 0, 5, 0, 0], |
408 |
409 |
[7, 13, 16, 1, 3, 0, 5, 0, 0, 0, 15, 0, 0, 0, 11, 0], |
409 |
410 |
[0, 0, 0, 5, 9, 16, 0, 0, 10, 0, 0, 6, 11, 7, 0, 15], |
410 |
411 |
[10, 0, 15, 0, 8, 0, 2, 0, 0, 7, 0, 0, 14, 16, 1, 0], |
411 |
412 |
[8, 0, 0, 0, 7, 12, 0, 0, 9, 0, 5, 14, 0, 0, 0, 13], |
412 |
413 |
[14, 0, 0, 3, 0, 0, 0, 1, 0, 16, 13, 2, 0, 0, 0, 0] |
413 |
414 |
] |
414 |
415 |
|
+ |
416 |
|
415 |
417 |
""" |
416 |
418 |
sudoku = [ |
417 |
419 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 19, 0, 0, 0, 20, 0], |
418 |
420 |
[0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 17, 0], |
419 |
421 |
[0, 0, 0, 0, 0, 0, 10, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
420 |
422 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 18, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
421 |
423 |
[0, 0, 23, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 12, 0, 0, 18, 0, 0, 0, 0, 0, 0], |
422 |
424 |
[0, 0, 0, 7, 0, 0, 0, 23, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
423 |
425 |
[0, 0, 10, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3, 0, 0, 0, 0, 0, 0, 0], |
424 |
426 |
[0, 0, 0, 0, 0, 0, 0, 12, 0, 0, 18, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 16, 0], |
425 |
427 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
426 |
428 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
427 |
429 |
[0, 9, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 17, 0, 0, 0, 0, 0, 12, 0, 0, 0], |
428 |
430 |
[0, 0, 12, 0, 15, 0, 0, 0, 0, 0, 14, 0, 0, 0, 5, 0, 0, 24, 3, 0, 0, 0, 0, 0, 0], |
429 |
431 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 9, 0, 0, 0, 0, 13, 0, 0, 5, 0, 0, 24, 3, 0], |
430 |
432 |
[0, 0, 8, 0, 0, 11, 0, 0, 0, 0, 0, 0, 0, 10, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
431 |
433 |
[0, 0, 0, 0, 0, 16, 0, 0, 0, 0, 0, 0, 19, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
432 |
434 |
[0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
433 |
435 |
[0, 18, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 17, 0, 0, 0], |
434 |
436 |
[0, 0, 0, 0, 0, 0, 0, 0, 12, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
435 |
437 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
436 |
438 |
[0, 5, 0, 13, 0, 0, 0, 0, 0, 0, 0, 0, 0, 19, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 1], |
437 |
439 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10], |
438 |
440 |
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
439 |
441 |
[0, 0, 0, 0, 0, 0, 0, 0, 20, 0, 0, 7, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
440 |
442 |
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 20, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], |
441 |
443 |
[0, 23, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] |
442 |
444 |
] |
443 |
445 |
""" |
444 |
446 |
print("You entered the following sudoku:") |
445 |
447 |
print_sudoku(sudoku) |
446 |
448 |
|
447 |
449 |
# OPTIMIZATION |
448 |
450 |
print("Collecting possibility table...") |
449 |
451 |
possibilities = [] |
450 |
452 |
for x in range(len(sudoku)): |
451 |
453 |
row = [] |
452 |
454 |
for y in range(len(sudoku[x])): |
453 |
455 |
entries = (collect_possible_entries(sudoku, x, y)) |
454 |
456 |
row.append(entries) |
455 |
457 |
assert len(entries) != 0 |
456 |
458 |
possibilities.append(row) |
457 |
459 |
print("Possibility table complete!") |
458 |
460 |
|
459 |
461 |
if recursive_solution(sudoku, possibilities): |
460 |
462 |
#if test_solution(sudoku): |
461 |
463 |
print("Sudoku solved!") |
462 |
464 |
print_sudoku(sudoku) |
463 |
465 |
else: |
464 |
466 |
print("Failed!") |
465 |
467 |
print_sudoku(sudoku) |
466 |
468 |
|
467 |
469 |